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Volume versus temperature graph of two moles of helium gas is as shown in figure. The ratio of heat absorbed and the work done by the gas in process `1-2` is A. `3`B. `5//2`C. `5//3`D. `7//2` |
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Answer» Correct Answer - B `V-T` graph is a straight line passing through origin.Hence, `VpropT` or `P` =constant `:. Dq=nC_(p)dT and dU=nC_(v)dT` `:. dW=dQ-dU=n(C_(p)-C_(v))dT` `:. (dQ)/(dW)=(nC_(p)dT)/(n(C_(p)-C_(v))dT)=(C_(p))/(C_(p)-C_(v))=(1)/(-1(C_(v))/(C_(p)))` `(C_(v))/(C_(P))=(3)/(5)` `:. (dQ)/(dW)=(1)/(1-3//5)=(5)/(2)`. |
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