1.

VW , U = 31/4harmonic oscillatorIf its mean K.E. isThe potential energy of a simple harmonicosat mean position is 3 joules. If its mean4 joules, its total energy will be :(1) 7J. (2) 8J (3) 10J (4) 110

Answer»

11j (option d ) is right answer

Energy in the state of rest, E1 = 3 J

KEat mean position, E2 = 2 x Mean KE = 2 x 4 = 8 J

Total energy, Et = E1 + E2 = 3 + 8 =11 J

Option 4)11 J is correct as:-Energy in the state of rest, E1 = 3 J

KEat mean position, E2 = 2 x Mean KE = 2 x 4 = 8 J

Total energy, Et = E1 + E2 = 3 + 8 =11 J



Discussion

No Comment Found

Related InterviewSolutions