WAP to accept two numbers and display the sum. Program will exit only

1.	WAP to accept two numbers and display the sum. Program will exit only if the sum is less than or equals to 0. please answer
Answer» Answer: import java. util. Scanner; PUBLIC class SumNum { public static void main(String[] args) { boolean a= true; while(a==true) { Scanner sc= new Scanner(System.in) ; System.out.print("ENTER the first number: ") ; DOUBLE num1= sc.nextDouble(); System.out.print("Enter the second number: ") ; double num2= sc.nextDouble(); double sum=num1+num2; if(sum<=0) { System.exit(0) ; } } } } hey as u said, the program EXITS ONLY WHEN SUM IS LESS THAN OR EQUAL TO zero

WAP to accept two numbers and display the sum. Program will exit only if the sum is less than or equals to 0. please answer

Answer»

Answer:

import java. util. Scanner;

PUBLIC class SumNum

{

public static void main(String[] args)

{

boolean a= true;

while(a==true)

{

Scanner sc= new Scanner(System.in) ;

System.out.print("ENTER the first number: ") ;

DOUBLE num1= sc.nextDouble();

System.out.print("Enter the second number: ") ;

double num2= sc.nextDouble();

double sum=num1+num2;

if(sum<=0)

{

System.exit(0) ;

}

hey as u said, the program EXITS ONLY WHEN SUM IS LESS THAN OR EQUAL TO zero