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InterviewSolution
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Water flowing steadily through a horizontal pipe of non-unifrom cross-section. If the pressure of water is `4xx10^(4)N//m^(2)` at a point where cross-section is `0.02 m^(2)` and velocity of flow is `2 ms^(-1)` . The pressure at a point where cross-section reduces to `0.01 m^(2)` is `3.4xx10^(n)` Pa. What is the value of n ? |
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Answer» Correct Answer - 4 Here, `a_(1) =0.02 m^(2), a_(2) =0.01 m^(2)`, `v_(1) =2 ms^(-1), v_(2)= ?` From Bernoullis theorem for horizontal flow `P_(1) +(1)/(2)rho v_(1)^(2) = P_(2) +(1)/(2)rho v_(2)^(2)` or `P_(2) = P_(1) + (1)/(2)rho 9v_(1)^(2) - v_(2)^(2)` `=4xx10^(4) + (1)/(2)xx10^(3) (2^(2) - 4^(2))` `=3.4xx10^(4)` Pa `=3.4xx10^(n)` Pa (Given) `:. n=4` |
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