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Water flows in a streamline manner through a capillary tube of radius a. The pressure difference being P and the rate of flow is Q . If the radius is reduced to `a//2` and the pressure difference is increased to 2P, then find the rate of flow.A. 4QB. QC. `Q/4`D. `Q/8` |
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Answer» Correct Answer - D As, `V=(pipr^4)/(8etal)` `therefore V prop pr^4 " " (eta " and l are constants")` `therefore V_2/V_1 = (p_2/p_1)(r_2/r_1)^4 = 2xx(1/2)^4 = 1/8` `rArr V_2 = Q/8` |
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