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At a depth of 1000 m in an ocean (a) what is the absolute pressure? (b) what is the gauge pressure? (c ) Find the force acting on the window of area `20 cm xx 20cm` of a submarine at this depth, the interior of which is maintained at sea-level atmospheric pressure. The density of sea water is `1.03 xx 10^(3) kg m^(-3)`, `g=10ms^(-2)`. Atmospheric pressure = `1.01 xx 10^(5) Pa`.A. 40 atmB. 52 atmC. 32 atmD. 62 atm |
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Answer» Correct Answer - B Absolute pressure `p=p_a+rhogh` here `p_a=1.01xx10^5Pa` `p=1.03xx10^3kgm^(-3)` `therefore " " p=1.01xx10^5Pa + 51.5 xx 10^5 Pa` `=1.01xx10^5 Pa + 51.5xx10^5 Pa` `=52.5xx10^5 pa = 52` atm |
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