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The rate of flow of liquid in a tube of radius r, length l, whose ends are maintained at a pressure difference P is `V = (piQPr^(4))/(etal)` where `eta` is coefficient of the viscosity and Q isA. 8B. `1/8`C. 16D. `1/16` |
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Answer» Correct Answer - B Rate of flow through a tube is given by `V=(pipr^4)/(8etal)` |
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