1.

A block is gently placed on a conveyor belt moving horizontal with constant speed After `t = 4s` the velocity of the block becomes equal to velocity of the belt If the coefficient of friction between the block and the belt is `mu = 0.2`, then the velocity of the conveyor belt is .A. `8ms^(-1)`B. `4ms^(-1)`C. `6ms^(-1)`D. `18ms^(-1)`

Answer» Correct Answer - A
Due to friction `(a-mug)` , veloctiy of block will become equal to velocity of bell . Relative motion between two will stop.
`therefore v=at = mugt = 0.2xx10xx4 = 8ms^(-1)`


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