Water from a tap emerges vertically downwards an intial speed of 1 m/s . The cross-sectional area of the tap is `10^(-4)m^(2)` . Assume that the pressure is contant throughout the stream of water and that the flow is steady . The cross-sectional area of the steam. `0.15` m below the tap isA. `5.0xx10^(-4)m^2`B. `1.0xx10^(-5)m^2`C. `5.0xx10^(-5)m^2`D. `2.0xx10^(-5)m^2`

Water from a tap emerges vertically downwards an intial speed of 1 m/s

1.	Water from a tap emerges vertically downwards an intial speed of 1 m/s . The cross-sectional area of the tap is `10^(-4)m^(2)` . Assume that the pressure is contant throughout the stream of water and that the flow is steady . The cross-sectional area of the steam. `0.15` m below the tap isA. `5.0xx10^(-4)m^2`B. `1.0xx10^(-5)m^2`C. `5.0xx10^(-5)m^2`D. `2.0xx10^(-5)m^2`
Answer» Correct Answer - C Decrease in potential energy = increasing in kinetic energy `therefore rhogh=1/2rho(V_f^2-V_i^2)` or `2(10)(0.15) = V_f^2 - (10)^2` or `V_f=2ms^(-1)` Now , from continuity equation. `A_1V_1A_2V_1 " or " A prop 1/v` Velocity has become two times . Hence , are of cross section will remain half .

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