1.

Wavelength of `K_alpha` line of an element is `lambda_0`. Find wavelength of `K_beta` - line for the same elemetn.

Answer» Correct Answer - A::B::C::D
`(1)/(lambda) prop((1)/(n_1^2) - (1)/(n_2^2))`
`:. (lambda_(K_beta)/(lambda_(K_alpha) = ((1//n_1^2 - 1 //n_2^2)/((1//n_1^2 -1//n_2^2)(K_Beta))`
`=((1-1//4)/(1-1//9)) = (27)/(32)`
`:. lambda_(K_beta) = (27)/(32) lambda_(K_alpha) = (27)/(32) lambda_0`
`:.lambda_(K_beta) = (27)/(32) lambda_(K_alpha) = (27)/(32)lambda_0`


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