WE-6:Sumofmagnitudesof the two forces actingat a point is 16 N. If the

1.	WE-6:Sumofmagnitudesof the two forces actingat a point is 16 N. If their resultant is normalto the smaller force, and has a magnitude 8Nthen the forces are( 2012E)
Answer» Let the force of smaller magnitude be A and the force of larger magnitude be B. here,it is clearly given that the resultant force is R perpendicular to small force. hence, we can say that b is the hyopetenuse . therefore, b² = R² + A²=> R² = b² - A²= 8²= 64 .......................... ( 1 ). here, it is also given thatA + B = 16 therefore , B = 16 - A ..........................( 2 ). Now, by substituting ( 2 ) in ( 1 ).we get, ( 16 - A ) ²- A² = 64=> 256 - 32A + A² - A² = 6432A = 256 - 64 = 192A = 192 / 32 = 6 hence, we get the resultB = 16 - A = 16 - 6 = 10 therefore, the magnitude of the two vectors are 6 and 10.

WE-6:Sumofmagnitudesof the two forces actingat a point is 16 N. If their resultant is normalto the smaller force, and has a magnitude 8Nthen the forces are( 2012E)

Answer»

Let the force of smaller magnitude be A and the force of larger magnitude be B.

here,it is clearly given that the resultant force is R perpendicular to small force. hence, we can say that b is the hyopetenuse .

therefore, b² = R² + A²=> R² = b² - A²= 8²= 64 .......................... ( 1 ).

here, it is also given thatA + B = 16 therefore , B = 16 - A ..........................( 2 ).

Now, by substituting ( 2 ) in ( 1 ).we get,

( 16 - A ) ²- A² = 64=> 256 - 32A + A² - A² = 6432A = 256 - 64 = 192A = 192 / 32 = 6

hence, we get the resultB = 16 - A = 16 - 6 = 10

therefore, the magnitude of the two vectors are 6 and 10.

Discussion

No Comment Found

Related InterviewSolutions

7. A body has a weight 50 N in air. Afterimmersing completely in liquid its weight is20 N. Then, the buoyant force on the bodywill be
Name the particulate which causes the disease mentioned below:(a)minamata (b)silicosis.
- Where does a body weight more at the surface of the carth or in a mine?
DelyAbody79entire chainthe ch.57. A body of mass 50gm collides elastically with anotherbody of mass 30 gm at rest. Then the percentage lossof the velocity of the colliding body during collision is1) 25% 2) 75% 3) 50% 4) 67%3) 120380.beide
What will be the acceleration of a body of mass5 kg if a force of 200 N is applied on it?
Rig. 5.168.13 Two bodles of masses 10 kg and 20 kg respectively kept on a smooth, hortzontalsurface are tied to the ends of a light string a horizontal force F 600 Nsapplied to lu A (t) B along the direction of string. What is the tension in thestring in each case
culate the gravitational force befween two protons kept at a distance67 x 10-27 kg. (1 femtometre = 10-15 m)
15. A uniform chain of length 2 m is kept on atable such that a length of 60 cm hangs freelyfrom the edge of the table. The total mass ofthe chain is 4 kg. What is the work done inpulling the entire chain onto the table ?(g = 10 m/s)1) 7.2J273.63) 120J4) 1200
Two block of mass 3 kg and 6 kg respectively are placed on a smooth 1.0 m/shorizontal surface. They are connected by a light spring of force 3 kgconstant k 200 N/m. Initially the spring is unstretched. The indicatedzmvelocities are imparted to the blocks. The maximum extension of thespring will be:A30 cm(C) 20 cm2.0 mls(B) 25 cm(D) 15 cm
88. A piece of stone is thrown vertically upwards. It reaches the maximum height in 3 seconds. If the accelerationof the stone be 9.8 m/s directed towards the ground, calculate the initial velocity of the stone with which itis thrown upwards.