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we read the period of oscillation of a simple pendulum .In successive measurements ,the reading turn out to be 2.63s,2.56s,2.42s,2.71s . calculate the absolute errors relative error or percentage error. |
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Answer» The MEAN PERIOD of oscillation will be T=2.63+2.56+2.42+2.71+2.8/5=2.62 secThe ERRORS in the measurement wil be 2.63-2.62=.01sec2.56-2.62=-.06sec2.42-2.62=-.2sec2.71-2.62=.09sec2.80-2.62=.18 secso mean of absolute error will be .11secHence Period of oscillation will be (2.62±0.11)Therefore T=2.6±.1srelative error or percentage error is GIVEN by=0.1/2.6*1004% |
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