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What angle will the free surface of a liquid subtend with the horizontal when the liquid in a container is moving horizontally with constat ac celeration a as shown in fig. |
Answer» Consider a horizontal liquid cylinder in the liquid, of length L area of cross-section A. Let `h_(1)`and `h_(2)` be the heights of liquid column at the ends of cylinder fro the surface of liquid as shown in fig. for the translatory motion of cylinder with ac celeratoin a. `F_(1)-F_(2) = ma` or, `P_(1)A-P_(2)A = AL rho a` or `(h_(1)rho g - h_(2)rho g)A =AL rho a` `[ :. P = h rho g]` or `(h_(1)-h_(2))g = La` or `(h_(1)-h_(2))/(L) = a/g` From fig, ` tan theta = (h_(1)-h_(2))/(L) = a/g` so, `theta = tan^(-1) a//g`. |
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