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What are the dimensions of the quantity l√l/g,l being the length and g the acceleration due to gravity |
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Answer» Answer: The dimensions of L × √(l/g) are [L][T] Explanation: We have to find the dimensions of the quantity l\times \sqrt{l/g}l× l/g
We know that Dimension of LENGTH l = [L][L] Dimensions of acceleration due to GRAVITY g = [LT^{-2}][LT −2 ] Therefore, dimensions of l × √(l/g) =[L]\times\sqrt{[L]/[LT^{-2}]}=[L]× [L]/[LT −2 ]
=[L]\times\sqrt{[T^{2}]}=[L]× [T 2 ]
=[L]\times{[T^{2}]^{1/2} =[L][T]=[L][T] Therefore the dimensions of l × √(l/g) are [L][T] |
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