1.

What are the respective number of `alpha` and `beta`-particles emitted in the following radioactive decay?A. (a) 6 and 8B. (b) 6 and 6C. (c) 8 and 8D. (d) 8 and 6

Answer» Correct Answer - D
Let `n-alpha` particles and `m-beta` particles are emitted.
Then,
`90-2n+m=80` …(i)
`200-4n=168` …(ii)
Solving Eqs. (i) and (ii), we get
`n=8` and `m=6`


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