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What average force is necessary to stop a bulletof mass 20 gm and speed 250 m/sec as it pen-etrates wood to a distance of 12 cm:(a) 3.4 x103 newton(c) 4.0 x10° newton(b) 5.2 x103 newton(d) 3.6 x 103 newton |
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Answer» Using kinematics eq.v^2 =u^2 - 2as0 = (250 )^2 - 2*0.12*a0.24a=62500a= 62500/0.24nowF = ma= 20/1000 * 62500/0.24solve itF = 5208 N |
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