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What is `(1111)_(2)+(1001)_(2)-(1010)_(2)` equal to ?A. `(111)_(2)`B. `(1100)_(2)`C. `(1110)_(2)`D. `(1010)_(2)` |
Answer» Correct Answer - C Since, `(1111)_(2)=1xx2^(3)+1xx2^(2)+1xx2^(1)+1xx2^(0)` `=8+4+2+1=15` `(1001)_(2)=1xx2^(3)+0xx2^(2)+0xx2^(1)+1xx2^(0)=8+1=9` `and (1010)_(2)=1xx2^(3)+0xx2^(2)+1xx2^(1)+0xx2^(0)=8+2=10` `therefore (1111)_(2)+(1001)_(2)-(1010)_(2)=15+9-10=14` `therefore (14)_(10)=(1110)_(2)` |
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