What is equation of latus rectums of hyperbola \((\frac{x}{9})^2-(\frac{y}{16})^2\)=1?(a) x=±5(b) y=±5(c) x=±2(d) y=±2I have been asked this question by my college professor while I was bunking the class.Asked question is from Conic Sections in chapter Conic Sections of Mathematics – Class 11

What is equation of latus rectums of hyperbola \((\frac{x}{9})^2-(\fra

1.	What is equation of latus rectums of hyperbola \((\frac{x}{9})^2-(\frac{y}{16})^2\)=1?(a) x=±5(b) y=±5(c) x=±2(d) y=±2I have been asked this question by my college professor while I was bunking the class.Asked question is from Conic Sections in chapter Conic Sections of Mathematics – Class 11
Answer» Correct CHOICE is (a) x=±5 Best EXPLANATION: COMPARING the equation with \((\frac{x}{a})^2-(\frac{y}{b})^2\)=1, we get a=3 and b=4. For HYPERBOLA, c^2=a^2+b^2= 9+16=25 => c=5. Equation of LATUS rectum x=±c i.e. x= ±5.

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