What is length of latus rectum for ellipse \((\frac{x}{25})^2+(\frac{y}{16})^2\)=1?(a) 25/2(b) 32/5(c) 5/32(d) 8/5This question was addressed to me in an interview for internship.This is a very interesting question from Conic Sections topic in portion Conic Sections of Mathematics – Class 11

What is length of latus rectum for ellipse \((\frac{x}{25})^2+(\frac{y

1.	What is length of latus rectum for ellipse \((\frac{x}{25})^2+(\frac{y}{16})^2\)=1?(a) 25/2(b) 32/5(c) 5/32(d) 8/5This question was addressed to me in an interview for internship.This is a very interesting question from Conic Sections topic in portion Conic Sections of Mathematics – Class 11
Answer» CORRECT CHOICE is (b) 32/5 The best explanation: We KNOW, LENGTH of latus rectum = 2b^2/a. So, length of latus rectum of given ELLIPSE = 2*42/5 = 32/5.

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What is length of latus rectum for ellipse \((\frac{x}{25})^2+(\frac{y}{16})^2\)=1?(a) 25/2(b) 32/5(c) 5/32(d) 8/5This question was addressed to me in an interview for internship.This is a very interesting question from Conic Sections topic in portion Conic Sections of Mathematics – Class 11

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