What is length of latus rectum for hyperbola \((\frac{x}{9})^2-(\frac{y}{16})^2\)=1?(a) 25/2(b) 32/3(c) 5/32(d) 8/5The question was asked in final exam.This intriguing question comes from Conic Sections in chapter Conic Sections of Mathematics – Class 11

What is length of latus rectum for hyperbola \((\frac{x}{9})^2-(\frac{

1.	What is length of latus rectum for hyperbola \((\frac{x}{9})^2-(\frac{y}{16})^2\)=1?(a) 25/2(b) 32/3(c) 5/32(d) 8/5The question was asked in final exam.This intriguing question comes from Conic Sections in chapter Conic Sections of Mathematics – Class 11
Answer» Right choice is (B) 32/3 For explanation I WOULD say: Comparing the equation with \((\frac{x}{a})^2-(\frac{y}{b})^2\)=1, we get a=3 and b=4. We know, length of LATUS rectum = 2b^2/a. So, length of latus rectum of given HYPERBOLA = 2*42/3 = 32/3.

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