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What is likely to be principal quantum number for a circular orbit of diameter `20.6nm` of the hydrogen atom. If we assume Bohr orbit to be the same as that represented by the principal quantum number?A. 10B. 14C. 12D. 16 |
Answer» Correct Answer - B `r_(n) = 0.529 xx n^(2)A^(@)`, diameter =` 2r, r =("diameter")/(2)` |
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