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What is relative pressure at 1600ft? (P1600=95602 N/m^2)(a) 0.9453(b) 0.9858(c) 0.9435(d) 0.9595I have been asked this question during an online interview.I'd like to ask this question from Standard Atmospheric Model in chapter Atmosphere and Air Data Measurement of Aircraft Performance

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Right OPTION is (c) 0.9435

The best I can explain: The answer is 0.9435.

Given P1600=101325 N/m^2,

From relative pressure (δ)=\(\FRAC{P_{1600}}{p_0}\)

δ=\(\frac{95602}{101325}\)=0.9435.



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