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What is the acute angle between the two straight lines y = ( ) 2– 3 x + 5 and y = ( ) 2 3 + x – 7 ?(a) 60° (b) 45° (c) 30° (d) 15° |
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Answer» (a) 60º The two lines are: y = \((2-\sqrt3)\) \(x\) + 5 ...(i) y = \((2-\sqrt3)\) \(x\) – 7 ...(ii) Slope of line (i), m1 = \(2-\sqrt3\) Slope of line (ii), m2 = \(2+\sqrt3\) If θ is the angle between the two lines, then tan θ = \(\big|\frac{m_1-m_2}{1+m_1m_2}\big|\) = \(\bigg|\frac{(2-\sqrt3)-(2+\sqrt3)}{1+(2-\sqrt3)(2+\sqrt3)}\bigg|\) = \(\bigg|\frac{-2\sqrt3}{1+1}\bigg|=\sqrt3\) ∴ θ = –1 tan ( 3) = 60º. |
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