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What is the average oxidation state of S in Na2S6O6?(a) 5(b) 0(c) 5/2(d) 2This question was addressed to me in exam.This intriguing question originated from Redox Reactions in section Redox Reactions of Chemistry – Class 11

Answer»

The CORRECT answer is (c) 5/2

The explanation is: the AVERAGE Oxidation state of elements in a compound is the average of the DIFFERENT oxidation States. The average oxidation state of S in Na2S6O6 is X. 2(1) + 4x + 6(-2) = 0; x = 5/2. The average Oxidation state of sulfur here is 5/2.



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