What is the de – Broglie wavelength of a proton accelerated through a potential difference of 2 kV?(a) 0.65 × 10^-13 m(b) 0.65 × 10^-10 m(c) 0.65 × 10^-11 m(d) 0.65 × 10^-20 mI have been asked this question in class test.The question is from Wave Nature of Matter in chapter Dual Nature of Radiation and Matter of Physics – Class 12

What is the de – Broglie wavelength of a proton accelerated through

1.	What is the de – Broglie wavelength of a proton accelerated through a potential difference of 2 kV?(a) 0.65 × 10^-13 m(b) 0.65 × 10^-10 m(c) 0.65 × 10^-11 m(d) 0.65 × 10^-20 mI have been asked this question in class test.The question is from Wave Nature of Matter in chapter Dual Nature of Radiation and Matter of Physics – Class 12
Answer» The correct CHOICE is (b) 0.65 × 10^-10 m The BEST explanation: Given: charge of PROTON = 1.6 × 10^-19; MASS of proton = 1.6 × 10^-27; V = 2 kV λ=\(\frac {h}{p} = \frac {h}{\sqrt {2mE}} = \frac {h}{\sqrt {2mqV}}\) λ=\(\frac {6.6 \times 10^{-34}}{\sqrt {2\times (1.6 \times 10^{-27})\times (1.6 \times 10^{-19}) \times 2000}}\) λ=0.65 × 10^-12m Therefore, the wavelength is 0.65 × 10^-12 m.

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