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InterviewSolution
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What is the difference in `pH` for `1//3` and `2//3` stages of neutralization of `0.1 M CH_(3)COOH` with `0.1 M NaOH`?A. `2 log 3`B. `2 log (1//4)`C. `2 log (2//3)`D. `2 log 2` |
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Answer» Correct Answer - D `CH_(3)COOH+OH^(-) rarrCH_(3)COO^(-)+H_(2)O` Difference in `pH` between `(1)/(3)` and `(2)/(3)` stages of neutralisation ` =[pK_(a)+log``((2//3)/(1//3))]-pK_(a)+log``((1//3)/(2//3))=2 log 2` |
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