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What is the energy change in the aircraft when the thrust is 244N and the distance travelled is 1230km?(a) 198000 N-Km(b) 484000 N-Km(c) 300120 N-Km(d) 234553 N-KmI got this question during a job interview.The query is from Estimation of Take-off Distances topic in chapter Take-off and Landing Performance of Aircraft Performance

Answer»

The CORRECT CHOICE is (c) 300120 N-Km

For EXPLANATION: The ANSWER is 300120 N-Km. USE the formula ΔE=T x S. Given T=244 N and S=1230 km.

On substituting we get ΔE=244 x 1230.

On solving we get ΔE=300120 N-Km.



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