1.

What is the equation of the straight line passing through the point (4, 3) and making intercepts on the co-ordinates axes whose sum is –1 ?

Answer»

Let the x-intercept = a. Then y-intercept = –1 – a 

The equation of the required line is \(\frac{x}{a}\) + \(\frac{y}{-1-a}\) = 1

Given, it passes through (4, 3), so,

\(\frac{4}{a}\) + \(\frac{3}{-1-a}\) = 1

⇒ – 4 – 4a + 3a = – a – a2 

⇒ a2 – 4 = 0 

⇒ (a + 2) (a – 2) = 0 

⇒ a = –2, or 2.

When a = 2, required line is \(\frac{x}{2}\) - \(\frac{y}{3}\) = 1

When a = –2, required line is \(\frac{x}{-2}\) + \(\frac{y}{3}\) = 1



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