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What is the equation of the straight line passing through the point (4, 3) and making intercepts on the co-ordinates axes whose sum is –1 ? |
Answer» Let the x-intercept = a. Then y-intercept = –1 – a The equation of the required line is \(\frac{x}{a}\) + \(\frac{y}{-1-a}\) = 1 Given, it passes through (4, 3), so, \(\frac{4}{a}\) + \(\frac{3}{-1-a}\) = 1 ⇒ – 4 – 4a + 3a = – a – a2 ⇒ a2 – 4 = 0 ⇒ (a + 2) (a – 2) = 0 ⇒ a = –2, or 2. When a = 2, required line is \(\frac{x}{2}\) - \(\frac{y}{3}\) = 1 When a = –2, required line is \(\frac{x}{-2}\) + \(\frac{y}{3}\) = 1 |
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