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What is the equilibrium constant, K for the following reaction at 400 K? `2NOCl (g) hArr 2NO(g)+Cl_(2)(g)` `DeltaH=77.2" kJ "mol^(-1) and DeltaS=122JK^(-1)mol^(-1)` at 400K.A. `-3.708`B. `1.95xx10^(-4)`C. `2.8xx10^(4)`D. `1.67xx10^(-5)` |
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Answer» Correct Answer - B `DeltaG=DeltaH-TDeltaS` `=77.2-400xx122xx10^(-3)` `=+28.4kJ" "mol^(-1)=28400" J "mol^(-1)` Further, `DeltaG=-2.303RTlogK` or `28400=-2.303xx8.314xx400xxlogK` `logK=-(28400)/(2.303xx8.314xx400)` `logK=-3.708` `K=`Antilog (-3.708)`=1.95xx10^(-4)` |
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