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What is the equivalent capacitance when the 2 capacitors are connected in series?(a) Cs = C1 + C2(b) Cs = \(\frac {1}{C_1} + \frac {1}{C_2}\)(c) Cs = C1 + \(\frac {1}{C_2}\)(d) Cs = \(\frac {1}{C_1}\) + C2The question was posed to me in an interview for internship.Origin of the question is Combination of Capacitors topic in chapter Electrostatic Potential and Capacitance of Physics – Class 12

Answer»

Correct answer is (B) Cs = \(\frac {1}{C_1} + \frac {1}{C_2}\)

For explanation: When 2 capacitors are connected in SERIES, the equivalent capacitance Cs is given by

Cs = \(\frac {1}{C_1} + \frac {1}{C_2}\)

When the capacitors are connected in series, the charge PASSING through each capacitor is the same.



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