What is the excess air factor in the case of a two-stroke engine if the delivery ratio is 1.7?(a) 1.0(b) 0.8(c) 0.7(d) 0.9The question was posed to me in quiz.I would like to ask this question from 2 Stroke Engines in portion Internal Combustion Engines of Automobile Engineering

What is the excess air factor in the case of a two-stroke engine if th

1.	What is the excess air factor in the case of a two-stroke engine if the delivery ratio is 1.7?(a) 1.0(b) 0.8(c) 0.7(d) 0.9The question was posed to me in quiz.I would like to ask this question from 2 Stroke Engines in portion Internal Combustion Engines of Automobile Engineering
Answer» CORRECT answer is (c) 0.7 To explain: Delivery ratio = Rdel = 1.7, EXCESS sir factor = λ. The relation between the Rdel and λ is λ = Rdel – 1 = 1.7 – 1 = 0.7. The delivery ratio is the ratio of the air delivered to the reference volume or ratio of the mass of fresh air delivered to the reference mass. Rdel = Vdel / Vref or Rdel = Mdel / Mref.

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What is the excess air factor in the case of a two-stroke engine if the delivery ratio is 1.7?(a) 1.0(b) 0.8(c) 0.7(d) 0.9The question was posed to me in quiz.I would like to ask this question from 2 Stroke Engines in portion Internal Combustion Engines of Automobile Engineering

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