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What is the frequency of light emitted when an electron in a hydrogen atom jumps from the 3^(rd) orbit to the 2^nd orbit ?

Answer»

SOLUTION :`E_3-E_2=-21.72xx10^(-19)((1)/(9)-(1)/(4))`
`21.72xx10^(-19)XX(5)/(36)`
`therefore` Difference in energy , `E_3-E_2-3.01xx10^(-19)J`
According to Plank's eqution , `DeltaE=hv`
`3.01xx10^(-19)=6.625 xx10^(-34)v`
FREQUENCY, (v) `=(3.01xx13^(-19))/(6.625xx10^(-34))=4.5xx10^(14-1)s`.


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