1.

What is the intrinsic stand-off ratio(η) of a unijunction transistor when RB1 = 10kΩ and RBB = 15kΩ?(a) 0.67(b) 0.55(c) 0.80(d) 0.44This question was addressed to me during an interview for a job.This interesting question is from The Unijunction Transistors in portion Field-Effect Transistors of Electronic Devices & Circuits

Answer»

The CORRECT option is (a) 0.67

To elaborate: The intrinsic stand-off ratio(η) is equal to the ratio RB1 / RBB. Standard VALUES of η RANGE from 0.5 to 0.8. Given RB1 = 10kΩ and RBB = 15kΩ:

η = RB1 / RBB = 10 / 15 = 0.67



Discussion

No Comment Found

Related InterviewSolutions