1.

What is the mass of 0.5 moles of sucrose (C_(12)H_(22)O_(11))?

Answer»

Solution : MOLAR mass of sucrose = `(12 xx 12) + (22 xx 1) + (11 xx 16)`
= 144 + 22 + 176 = 342 G
Mass = `"molar mass" xx "NUMBER of moles"`
`= 342 xx 0.5` = 171 g
The mass of 0.5 moles of sucrose is 171 g.


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