the maximum value of 24 sin x + 10 cos x ?Answer :For an equation a sin x + b cos x :Maximum value = √ ( a² + b² )Given : a = 24             b = 10Maximum value = √ ( 24² + 10² )                           =  √ ( 576 + 100 )                           = √ 676                           = ± 26The maximum value can be 26 .CODE :import java.util.*;class switch_mania{public STATIC void main(String args[]){Scanner sc=new Scanner(System.in);System.out.println("Enter a number");int n=sc.nextInt();System.out.println("Enter 1 to print reverse , 2 to print number without zeroes and 3 to check pallindrome ");int ch=sc.nextInt();switch(ch){case 1:while(n>0){int d=n%10;rev=(rev*10)+d;n=n/10;}System.out.println("Reverse of the number is "+rev);break;case 2:System.out.println("The zeroes are removed");while(n>0){int d=n%10;rev=(rev*10)+d;n=n/10;}while(rev>0){int d=rev%10;if(d!=0){System,out.print(d);}rev=rev/10;}break;case 3:int cpy=n;while(n>0){int d=n%10;rev=(rev*10)+d;n=n/10;}if(cpy==rev){System.out.println("Pallindrome number");}else{System.out.println("Not a pallindrome number");}break;}DEFAULT:System.out.println("Invalid CHOICE");}}}THANK you !