1.

What is the mean life (in min.) of `Co^(55)` radionuclide, if its activity is known to decrease `4.0%` per hour? The decay product is non-radioactive. [ln 100 =4.6, ln 96=4.56]

Answer» Correct Answer - [1500]
`t_("avg")=(1)/(lambda) " " lambda xx 1 =ln(100)/(96) " " lambda=0.04 hr^(-1)`
`t_("avg")=(1)/(lambda)=25 xx60 xx=1500`


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