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What is the melting point of benzene if `DeltaH_("fusion")= 9.95kJ//mol` and `DeltaS_("fusion")= 35.7J//K-"mol"`A. `278.7^(@)C`B. `278.7^(@)K`C. 300 KD. 298 K |
Answer» Correct Answer - B at M.P. `DeltaS_("fusion")=(DeltaH_("fusion"))/(T)` `implies" "T=(DeltaH)/(DeltaS)=(9.95 xx1000)/(35.7)=278.7 K` |
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