1.

What is the middle term of (x^2 + x)^3?(a) 3x^4(b) 6x^4(c) 4x^4(d) 3x^6This question was addressed to me during an online interview.Asked question is from Binomial Theorem topic in chapter Binomial Theorem of Mathematics – Class 11

Answer»

Correct choice is (a) 3x^4

Easy explanation: SINCE the power is odd, there will be even NUMBER of terms and TWO middle terms.

r = \(\FRAC{n + 1}{2}\) and r = \(\frac{n – 1}{2}\)

Here n = 3

Therefore, r = 2 and r = 1.

When r = 2, ^3C2 (x^2)^3 – 2(x)^2 = 3x^4

When r = 1, ^3C1 (x^2)^3 – 1(x)^1 = 3x^5



Discussion

No Comment Found

Related InterviewSolutions