1.

What is the middle term of (xyz + 3)^80?(a) ^80C41 (xyz)^41 (3)^39(b) ^80C40 (xyz)^40 (3)^40(c) ^80C39 (xyz)^39 (3)^40(d) ^80C41 (xyz)^41 (3)^40The question was asked in an interview.I need to ask this question from Binomial Theorem topic in section Binomial Theorem of Mathematics – Class 11

Answer»

Correct choice is (B) ^80C40 (xyz)^40 (3)^40

Explanation: Since the POWER is even, there are odd NUMBER of terms.

The middle term is the \((\FRAC{n}{2} + 1)^{th}\) term.

= \((\frac{80}{2} + 1)^{th}\) term

= 41^st term

The 41^st term = ^80C40 (xyz)^40 (3)^40



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