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What is the minimum height of any point on the curve `y=x^2+6x-5`above the x-axisdv? |
Answer» `y = -x^(2) + 6x - 5` `=4- (x -3)^(2)` Now `(x - 3)^(2) ge 0` for all real x, Hence, the maximum value of `y(or - x^(2) + 6x - 5) ` is 4, which is the maximum height of the graph above x-axis. |
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