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    				| 1. | 
                                    What is the minimun wavelength of X- rays obtained from Mo target with electrons accelerated by 35KeV potential difference. | 
                            
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Answer»  f = [1.6 x 10^-19 x 3.5 x 10^4]/ 6.63 x 10^-34 = 8.4x10^18 Hz Therefore the wavelength l (= c/f) is 3 * 10^8/8.4x10^18 Hz = 0.357 x 10-10 m = 0.036 nm (compared with some 600 nm for yellow light).  | 
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