What is the `[OH^(-)]` in the final solution prepared by mixing `20.0 mL` of `0.050 M HCl` with `30.0 mL` of `0.10 M Ba(OH)_(2)`?A. `0.10 M`B. `0.40 M`C. `0.0050 M`D. `0.12 M`

What is the `[OH^(-)]` in the final solution prepared by mixing `20.0

1.	What is the `[OH^(-)]` in the final solution prepared by mixing `20.0 mL` of `0.050 M HCl` with `30.0 mL` of `0.10 M Ba(OH)_(2)`?A. `0.10 M`B. `0.40 M`C. `0.0050 M`D. `0.12 M`
Answer» Correct Answer - A Number of milleequivalent of `HCl` `=20xx0.050xx1=1` Number of millequivalent of `Ba(OH)_(2)` `=2xx30xx0.1=6` milliequivalent of `Ba(OH)_(2)` `[OH^(-)]` of final solution `=` (milliequivalent of `HCl`)/(total volume) `=(6-1)/(50)=0.1 M`

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What is the `[OH^(-)]` in the final solution prepared by mixing `20.0 mL` of `0.050 M HCl` with `30.0 mL` of `0.10 M Ba(OH)_(2)`?A. `0.10 M`B. `0.40 M`C. `0.0050 M`D. `0.12 M`

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