What is the order of reaction for which rate becomes half if volume of the container having same amount of reactant is doubled? Assume gaseous phase reaction.

What is the order of reaction for which rate becomes half if volume of

1.	What is the order of reaction for which rate becomes half if volume of the container having same amount of reactant is doubled? Assume gaseous phase reaction.
Answer» Correct Answer - 1 Rate, For `I`: Let a mole of reactant in vessel of `V` litre `:. r_(1)=K[a/V]^(n) …(1)` For `II`: The volume is doubled, rate becomes half. `:. R_(1)/2=K[a/(2V)]^(n) …(2)` By eqs. (1) and (2) `2=2^(n)` or `n=1` Order of reaction =`1`

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What is the order of reaction for which rate becomes half if volume of the container having same amount of reactant is doubled? Assume gaseous phase reaction.

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