What is the output of the program in Turbo C (in DOS 16-bit OS)?

1.	What is the output of the program in Turbo C (in DOS 16-bit OS)?
Answer» Any pointer size is 2 bytes. (only 16-bit offset) So, char s1 = 2 bytes. So, char far s2; = 4 bytes. So, char huge *s3; = 4 bytes. A far, huge pointer has two parts: a 16-bit segment value and a 16-bit offset value. Since C is a compiler dependent language, it may give different output in other platforms. The above program works fine in Windows (TurboC), but error in Linux (GCC Compiler).

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