

InterviewSolution
Saved Bookmarks
1. |
What is the particular solution of the first order difference equation y(n)+ay(n-1)=x(n) where |a| |
Answer» CORRECT choice is (a) \(\frac{1}{1+a}\) u(n) To explain I would say: The assumed solution of the difference equation to the forcing equation x(n), called the particular solution of the difference equation is yp(n)=Kx(n)=Ku(n) (where K is a scale factor) Substitute the above equation in the given equation =>Ku(n)+aKu(n-1)=u(n) To determine K we MUST EVALUATE the above equation for any n>=1, so that no TERM vanishes. => K+aK=1 =>K=\(\frac{1}{1+a}\) Therefore the particular solution is yp(n)=\(\frac{1}{1+a}\) u(n). |
|