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What is the percentage of calcium in calcium carbonate (CaCO_(3)) ? |
Answer» Solution :Molecular mass of `CaCO_(3) = 40+ 12 + 3 xx 16 = 100 ` amu . Mass of calcium in 1 MOL of `CaCO_(3) = 40`G `THEREFORE` PERCENTAGE of calcium = `(40 xx 100)/(100) = 40` . |
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