1.

What is the percentage of calcium in calcium carbonate (CaCO_(3)) ?

Answer»

Solution :Molecular mass of `CaCO_(3) = 40+ 12 + 3 xx 16 = 100 ` amu .
Mass of calcium in 1 MOL of `CaCO_(3) = 40`G
`THEREFORE` PERCENTAGE of calcium = `(40 xx 100)/(100) = 40` .


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