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What is the probability of getting 2 heads and 1 tail when 3 coins are tossed?(a) \(\frac{1}{8}\)(b) \(\frac{1}{3}\)(c) \(\frac{3}{8}\)(d) \(\frac{3}{2}\)The question was asked by my school principal while I was bunking the class.I want to ask this question from Data Handling in section Data Handling of Mathematics – Class 8

Answer»

Right choice is (c) \(\frac{3}{8}\)

For explanation: A coin has TWO sides i.e. head and tail. When a coin is tossed, we can get either head or tail. The likelihood of getting either head or tail is equal. The outcomes are HHH, HHT, HTH, HTT, THH, THT, TTH, TTT. Hence, the probability of getting 2 heads and 1 tail when 3 coins are tossed is \(\frac{3}{8}\).



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