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What is the quantity of electricity in coulombs needed to reduce 1 mol of Cr2O72-? Consider the reaction: Cr2O72- +14H ++6e --> 2Cr3+ +8H2O |
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Answer» The given reaction is as follows: Cr2 O72- + 14H+ + 6e- → Cr3+ + 8H2O Therefore, to reduce 1 mole of Cr2 O72-, the required quantity of electricity will be: =6 F = 6 × 96487 C = 578922 C |
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