InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
What is the quantity of electricity in coulombs needed to reduce 1 mol of Cr2O72-? Consider the reaction: Cr2O72- +14H ++6e --> 2Cr3+ +8H2O |
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Answer» The given reaction is as follows: Cr2 O72- + 14H+ + 6e- → Cr3+ + 8H2O Therefore, to reduce 1 mole of Cr2 O72-, the required quantity of electricity will be: =6 F = 6 × 96487 C = 578922 C |
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| 2. |
Why does the conductivity of a solution decrease with dilution? |
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Answer» The conductivity of a solution is the conductance of ions present in a unit volume of the solution. The number of ions (responsible for carrying current) decreases when the solution is diluted. As a result, the conductivity of a solution decreases with dilution. |
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| 3. |
Can you store copper sulphate solutions in a zinc pot? |
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Answer» Zinc is more reactive than copper. Therefore, zinc can displace copper from its salt solution. If copper sulphate solution is stored in a zinc pot, then zinc will displace copper from the copper sulphate solution. Zn+CuSO4 ---> ZnSO4 +Cu Hence, copper sulphate solution cannot be stored in a zinc pot. |
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| 4. |
Given the standard electrode potentials, K +/K = −2.93V, Ag+/Ag = 0.80V, Hg2+/Hg = 0.79V Mg2+/Mg = −2.37 V, Cr 3+/Cr = − 0.74V Arrange these metals in their increasing order of reducing power. |
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Answer» The lower the reduction potential, the higher is the reducing power. The given standard electrode potentials increase in the order of K+/K < Mg2+/Mg < Cr3+/Cr < Hg2+/Hg < Ag+/Ag. Hence, the reducing power of the given metals increases in the following order: Ag < Hg < Cr < Mg < K |
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