What is the range of the power producing engine?(a) RP=\(\big[\frac{\eta}{C_P}E_{max}\big]\big\{\frac{2u^2}{u^4+1}\big\}\)lnω(b) RP=\(\big[\frac{\eta}{C_P}E_{max}\big]\big\{\frac{2u^3}{u^4+1}\big\}\)lnω(c) RP=\(\big[\frac{\eta}{C_P}\big]\big\{\frac{2u^2}{u^4+1}\big\}\)lnω(d) RP=\(\big[\frac{V_{mdi}}{C_P}E_{max}\big]\big\{\frac{2u^3}{u^4+1}\big\}\)lnωI had been asked this question during an interview for a job.The origin of the question is Cruising Performance topic in portion Cruising Performance of Aircraft Performance

What is the range of the power producing engine?(a) RP=\(\big[\frac{\e

1.	What is the range of the power producing engine?(a) RP=\(\big[\frac{\eta}{C_P}E_{max}\big]\big\{\frac{2u^2}{u^4+1}\big\}\)lnω(b) RP=\(\big[\frac{\eta}{C_P}E_{max}\big]\big\{\frac{2u^3}{u^4+1}\big\}\)lnω(c) RP=\(\big[\frac{\eta}{C_P}\big]\big\{\frac{2u^2}{u^4+1}\big\}\)lnω(d) RP=\(\big[\frac{V_{mdi}}{C_P}E_{max}\big]\big\{\frac{2u^3}{u^4+1}\big\}\)lnωI had been asked this question during an interview for a job.The origin of the question is Cruising Performance topic in portion Cruising Performance of Aircraft Performance
Answer» Right option is (a) RP=\(\big[\frac{\eta}{C_P}E_{max}\big]\big\{\frac{2u^2}{u^4+1}\big\}\)lnω The BEST explanation: The correct equation for range of thrust PRODUCING engine is given by the equation RP=\(\big[\frac{\eta}{C_P}E_{max}\big]\big\{\frac{2u^2}{u^4+1}\big\}\)lnω where V is true airspeed, C is SPECIFIC fuel CONSUMPTION, Emax is endurance, η is PROPELLER efficiency and ω is fuel ratio.

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